Math calculator needed

[sk8kidamh]

ok, take a number, multiply it by 2, add 5, multiply by 50, If your birthday has passed, add 1756, if it hasn't add 1755, now subtract you birth year, you should get your number followed by your age.

Now what i need is to find out how high this works up to, i know it works for all positive 1 digit numbers, i need to know, how high and how low it goes.

Thanks

[Woolfenstien]

This is the Homework Help forum.

Not the "Do my Homework for me plskthx" forum.

[Homer43]

I think it works for all numbers... even if you do a really small number (.00000000001) it seems to come out as your age then a number.

[gorgieboy]

It isn't working for me?

[Zapurdead]

It isn't working for me?
You have horrible math skills.
What's your age?
Has your birthday passed or not?

[sk8kidamh]

You have horrible math skills.
What's your age?
Has your birthday passed or not?

Has it ever occured to you that not everyone is a nerd in math.

There is no need to be that negative toward anyone.

[JoeyG]

ok, take a number, multiply it by 2, add 5, multiply by 50, If your birthday has passed, add 1756, if it hasn't add 1755, now subtract you birth year, you should get your number followed by your age.

You mean
100N + 2005 - [year of birth]

Assuming your age is under 100, 100N is redundant. So, either
2005 - [year of birth] or
2006 - [year of birth]

Doesn't take Einstein to figure out when that works...

[DarkReality]

How is 100N redundant if I'm younger than a 100? I can't expect to pick a random number and then subtract two constants from one another and then see my number in the result.

2005 (or 2006) - year of birth gives me my age and nothing more. It has nothing to do with the original "see the number you picked next to your age in the answer blol!".

The line "100N + 2005 - [year of birth]"

was the correct term.

Although it still doesn't take an IQ of 210 to see that it always works, so long as you're not older than 100.

[JoeyG]

How is 100N redundant if I'm younger than a 100? I can't expect to pick a random number and then subtract two constants from one another and then see my number in the result.

2005 (or 2006) - year of birth gives me my age and nothing more. It has nothing to do with the original "see the number you picked next to your age in the answer blol!".

The line "100N + 2005 - [year of birth]"

was the correct term.

Although it still doesn't take an IQ of 210 to see that it always works, so long as you're not older than 100.

What is "your number"? I assumed it had no relation to you, and therefore might as well be 0 all the time.

EDIT: Oh, "your number" is N. Never mind.

OP, use English. This isn't the first time I've failed to verbally abuse someone for abusing the language and ending up with some critical misunderstanding of the post.

[,killer,death,]

this is dumb it dosent work. if i choose the number 1 then it says im 62 and IM NOT!! im 13. it dosent work. its a waste of time.

[Choft]

I remember doing something like this. The answer came up with something about me liking chocalate.

[JoeyG]

this is dumb it dosent work. if i choose the number 1 then it says im 62 and IM NOT!! im 13. it dosent work. its a waste of time.

I just algebraically proved that it works for all integers >= 1. Are you spamming or can you honestly not do grade 5 math?

[/pisrich]

i used 140 and got like 570 or something. ya im 570. no one lived past 122!!!!!!!!!!! your teacher is wrong.

[Ovrlndnsea]

ok, take a number, multiply it by 2, add 5, multiply by 50, If your birthday has passed, add 1756, if it hasn't add 1755, now subtract you birth year, you should get your number followed by your age.

X
2X
2X+5
100X+250
Supposing my birthday has passed, we get
100X+2006
If I'm... say... 46 years old (I'm not) and the year is 2006, then
100X+46
Therefore, this works with starting numbers of positive integers, and ages 0 years through 99 years.

JoeyG, I just proved that it works for all integers >=1 when the age is between 0 and 99 inclusive. Not when the age is something else, like you said.

[JoeyG]

Ah. I forgot all the future people and centagenarians who frequent this board.

I don't believe I put any restrictions on the age, which I admit is the same as saying "anything will work", but at no point did I explicitly say that it'd work for more than 100.

I did, however, say that it will work for all integers N > 0.

Edit: By "N" I mean the magic number, not the age. I keep saying that and every time I read it it still isn't clear. The age is restricted to integers [0..100).

[Ovrlndnsea]

If you were correct, then that means that either your statment means nothing or that centagenarians and fetuses worked.

Therefore, either your statment means nothing or you were incorrect.

But yes, you are right in post #15. You didn't say that it works for an age over 100. However, if we assume that your answer is an answer and means something, then it is implied.

[DarkReality]

... what the ####? You two proved the same thing.

It works for numbers that have no more than two digits as 100N + (2006-YourYearOfBirth) will ALWAYS be N followed by two zeros plus your age (which has to have one or two digits in order to not change N).

So where exactly is the problem?

It's sort of trivial that it'll work for 0. 100*0=0, leaving you with todays year minus your birth year.

[sk8kidamh]

Guys this isnt ment to be a complicated hightech sorta thing, it is simple math, i was woundering what would happen with a simple problem when a bunch of geniuses did it, and now i know

[Red.Tide]

They explained how it works, that's how they 'did it'. Instead of going, 'wowomg kewl trick', they figured how it works, using algebra (which you probably haven't learned yet), and then used this knowledge to come up with the answer. I would say it works for all real numbers from 0 (including zero) to 100 (not including 100).

As for your 'simple math' claim, most of the people who helped you with this problem are probably older than you; it is like 'simple math' to them.